Optimal. Leaf size=233 \[ \frac{a \left (5 a^2 B-15 a b C-12 b^2 B\right ) \cot ^3(c+d x)}{15 d}+\frac{\left (3 a^2 b B+a^3 C-3 a b^2 C-b^3 B\right ) \cot ^2(c+d x)}{2 d}-\frac{\left (-3 a^2 b C+a^3 B-3 a b^2 B+b^3 C\right ) \cot (c+d x)}{d}+\frac{\left (3 a^2 b B+a^3 C-3 a b^2 C-b^3 B\right ) \log (\sin (c+d x))}{d}-x \left (-3 a^2 b C+a^3 B-3 a b^2 B+b^3 C\right )-\frac{a^2 (5 a C+7 b B) \cot ^4(c+d x)}{20 d}-\frac{a B \cot ^5(c+d x) (a+b \tan (c+d x))^2}{5 d} \]
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Rubi [A] time = 0.558215, antiderivative size = 233, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 7, integrand size = 40, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.175, Rules used = {3632, 3605, 3635, 3628, 3529, 3531, 3475} \[ \frac{a \left (5 a^2 B-15 a b C-12 b^2 B\right ) \cot ^3(c+d x)}{15 d}+\frac{\left (3 a^2 b B+a^3 C-3 a b^2 C-b^3 B\right ) \cot ^2(c+d x)}{2 d}-\frac{\left (-3 a^2 b C+a^3 B-3 a b^2 B+b^3 C\right ) \cot (c+d x)}{d}+\frac{\left (3 a^2 b B+a^3 C-3 a b^2 C-b^3 B\right ) \log (\sin (c+d x))}{d}-x \left (-3 a^2 b C+a^3 B-3 a b^2 B+b^3 C\right )-\frac{a^2 (5 a C+7 b B) \cot ^4(c+d x)}{20 d}-\frac{a B \cot ^5(c+d x) (a+b \tan (c+d x))^2}{5 d} \]
Antiderivative was successfully verified.
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Rule 3632
Rule 3605
Rule 3635
Rule 3628
Rule 3529
Rule 3531
Rule 3475
Rubi steps
\begin{align*} \int \cot ^7(c+d x) (a+b \tan (c+d x))^3 \left (B \tan (c+d x)+C \tan ^2(c+d x)\right ) \, dx &=\int \cot ^6(c+d x) (a+b \tan (c+d x))^3 (B+C \tan (c+d x)) \, dx\\ &=-\frac{a B \cot ^5(c+d x) (a+b \tan (c+d x))^2}{5 d}+\frac{1}{5} \int \cot ^5(c+d x) (a+b \tan (c+d x)) \left (a (7 b B+5 a C)-5 \left (a^2 B-b^2 B-2 a b C\right ) \tan (c+d x)-b (3 a B-5 b C) \tan ^2(c+d x)\right ) \, dx\\ &=-\frac{a^2 (7 b B+5 a C) \cot ^4(c+d x)}{20 d}-\frac{a B \cot ^5(c+d x) (a+b \tan (c+d x))^2}{5 d}+\frac{1}{5} \int \cot ^4(c+d x) \left (-a \left (5 a^2 B-12 b^2 B-15 a b C\right )-5 \left (3 a^2 b B-b^3 B+a^3 C-3 a b^2 C\right ) \tan (c+d x)-b^2 (3 a B-5 b C) \tan ^2(c+d x)\right ) \, dx\\ &=\frac{a \left (5 a^2 B-12 b^2 B-15 a b C\right ) \cot ^3(c+d x)}{15 d}-\frac{a^2 (7 b B+5 a C) \cot ^4(c+d x)}{20 d}-\frac{a B \cot ^5(c+d x) (a+b \tan (c+d x))^2}{5 d}+\frac{1}{5} \int \cot ^3(c+d x) \left (-5 \left (3 a^2 b B-b^3 B+a^3 C-3 a b^2 C\right )+5 \left (a^3 B-3 a b^2 B-3 a^2 b C+b^3 C\right ) \tan (c+d x)\right ) \, dx\\ &=\frac{\left (3 a^2 b B-b^3 B+a^3 C-3 a b^2 C\right ) \cot ^2(c+d x)}{2 d}+\frac{a \left (5 a^2 B-12 b^2 B-15 a b C\right ) \cot ^3(c+d x)}{15 d}-\frac{a^2 (7 b B+5 a C) \cot ^4(c+d x)}{20 d}-\frac{a B \cot ^5(c+d x) (a+b \tan (c+d x))^2}{5 d}+\frac{1}{5} \int \cot ^2(c+d x) \left (5 \left (a^3 B-3 a b^2 B-3 a^2 b C+b^3 C\right )+5 \left (3 a^2 b B-b^3 B+a^3 C-3 a b^2 C\right ) \tan (c+d x)\right ) \, dx\\ &=-\frac{\left (a^3 B-3 a b^2 B-3 a^2 b C+b^3 C\right ) \cot (c+d x)}{d}+\frac{\left (3 a^2 b B-b^3 B+a^3 C-3 a b^2 C\right ) \cot ^2(c+d x)}{2 d}+\frac{a \left (5 a^2 B-12 b^2 B-15 a b C\right ) \cot ^3(c+d x)}{15 d}-\frac{a^2 (7 b B+5 a C) \cot ^4(c+d x)}{20 d}-\frac{a B \cot ^5(c+d x) (a+b \tan (c+d x))^2}{5 d}+\frac{1}{5} \int \cot (c+d x) \left (5 \left (3 a^2 b B-b^3 B+a^3 C-3 a b^2 C\right )-5 \left (a^3 B-3 a b^2 B-3 a^2 b C+b^3 C\right ) \tan (c+d x)\right ) \, dx\\ &=-\left (a^3 B-3 a b^2 B-3 a^2 b C+b^3 C\right ) x-\frac{\left (a^3 B-3 a b^2 B-3 a^2 b C+b^3 C\right ) \cot (c+d x)}{d}+\frac{\left (3 a^2 b B-b^3 B+a^3 C-3 a b^2 C\right ) \cot ^2(c+d x)}{2 d}+\frac{a \left (5 a^2 B-12 b^2 B-15 a b C\right ) \cot ^3(c+d x)}{15 d}-\frac{a^2 (7 b B+5 a C) \cot ^4(c+d x)}{20 d}-\frac{a B \cot ^5(c+d x) (a+b \tan (c+d x))^2}{5 d}+\left (3 a^2 b B-b^3 B+a^3 C-3 a b^2 C\right ) \int \cot (c+d x) \, dx\\ &=-\left (a^3 B-3 a b^2 B-3 a^2 b C+b^3 C\right ) x-\frac{\left (a^3 B-3 a b^2 B-3 a^2 b C+b^3 C\right ) \cot (c+d x)}{d}+\frac{\left (3 a^2 b B-b^3 B+a^3 C-3 a b^2 C\right ) \cot ^2(c+d x)}{2 d}+\frac{a \left (5 a^2 B-12 b^2 B-15 a b C\right ) \cot ^3(c+d x)}{15 d}-\frac{a^2 (7 b B+5 a C) \cot ^4(c+d x)}{20 d}+\frac{\left (3 a^2 b B-b^3 B+a^3 C-3 a b^2 C\right ) \log (\sin (c+d x))}{d}-\frac{a B \cot ^5(c+d x) (a+b \tan (c+d x))^2}{5 d}\\ \end{align*}
Mathematica [C] time = 1.16752, size = 237, normalized size = 1.02 \[ \frac{20 a \left (a^2 B-3 a b C-3 b^2 B\right ) \cot ^3(c+d x)+30 \left (3 a^2 b B+a^3 C-3 a b^2 C-b^3 B\right ) \cot ^2(c+d x)-60 \left (-3 a^2 b C+a^3 B-3 a b^2 B+b^3 C\right ) \cot (c+d x)+60 \left (3 a^2 b B+a^3 C-3 a b^2 C-b^3 B\right ) \log (\tan (c+d x))-15 a^2 (a C+3 b B) \cot ^4(c+d x)-12 a^3 B \cot ^5(c+d x)+30 i (a+i b)^3 (B+i C) \log (-\tan (c+d x)+i)+30 (b+i a)^3 (B-i C) \log (\tan (c+d x)+i)}{60 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.115, size = 376, normalized size = 1.6 \begin{align*} -{\frac{Ba{b}^{2} \left ( \cot \left ( dx+c \right ) \right ) ^{3}}{d}}-{\frac{B\cot \left ( dx+c \right ){a}^{3}}{d}}-B{a}^{3}x-C{b}^{3}x-{\frac{B{a}^{3}c}{d}}-{\frac{3\,Ca{b}^{2} \left ( \cot \left ( dx+c \right ) \right ) ^{2}}{2\,d}}-{\frac{3\,B{a}^{2}b \left ( \cot \left ( dx+c \right ) \right ) ^{4}}{4\,d}}-{\frac{C{a}^{2}b \left ( \cot \left ( dx+c \right ) \right ) ^{3}}{d}}-{\frac{C{b}^{3}c}{d}}+{\frac{B{a}^{3} \left ( \cot \left ( dx+c \right ) \right ) ^{3}}{3\,d}}+3\,Ba{b}^{2}x+3\,Cx{a}^{2}b+{\frac{C{a}^{3}\ln \left ( \sin \left ( dx+c \right ) \right ) }{d}}-{\frac{B{b}^{3}\ln \left ( \sin \left ( dx+c \right ) \right ) }{d}}+{\frac{C{a}^{3} \left ( \cot \left ( dx+c \right ) \right ) ^{2}}{2\,d}}-{\frac{C\cot \left ( dx+c \right ){b}^{3}}{d}}-{\frac{C{a}^{3} \left ( \cot \left ( dx+c \right ) \right ) ^{4}}{4\,d}}-{\frac{B{b}^{3} \left ( \cot \left ( dx+c \right ) \right ) ^{2}}{2\,d}}-{\frac{B{a}^{3} \left ( \cot \left ( dx+c \right ) \right ) ^{5}}{5\,d}}-3\,{\frac{Ca{b}^{2}\ln \left ( \sin \left ( dx+c \right ) \right ) }{d}}+{\frac{3\,B{a}^{2}b \left ( \cot \left ( dx+c \right ) \right ) ^{2}}{2\,d}}+3\,{\frac{C\cot \left ( dx+c \right ){a}^{2}b}{d}}+3\,{\frac{B{a}^{2}b\ln \left ( \sin \left ( dx+c \right ) \right ) }{d}}+3\,{\frac{Ba{b}^{2}c}{d}}+3\,{\frac{C{a}^{2}bc}{d}}+3\,{\frac{B\cot \left ( dx+c \right ) a{b}^{2}}{d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.6342, size = 338, normalized size = 1.45 \begin{align*} -\frac{60 \,{\left (B a^{3} - 3 \, C a^{2} b - 3 \, B a b^{2} + C b^{3}\right )}{\left (d x + c\right )} + 30 \,{\left (C a^{3} + 3 \, B a^{2} b - 3 \, C a b^{2} - B b^{3}\right )} \log \left (\tan \left (d x + c\right )^{2} + 1\right ) - 60 \,{\left (C a^{3} + 3 \, B a^{2} b - 3 \, C a b^{2} - B b^{3}\right )} \log \left (\tan \left (d x + c\right )\right ) + \frac{60 \,{\left (B a^{3} - 3 \, C a^{2} b - 3 \, B a b^{2} + C b^{3}\right )} \tan \left (d x + c\right )^{4} + 12 \, B a^{3} - 30 \,{\left (C a^{3} + 3 \, B a^{2} b - 3 \, C a b^{2} - B b^{3}\right )} \tan \left (d x + c\right )^{3} - 20 \,{\left (B a^{3} - 3 \, C a^{2} b - 3 \, B a b^{2}\right )} \tan \left (d x + c\right )^{2} + 15 \,{\left (C a^{3} + 3 \, B a^{2} b\right )} \tan \left (d x + c\right )}{\tan \left (d x + c\right )^{5}}}{60 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.12562, size = 620, normalized size = 2.66 \begin{align*} \frac{30 \,{\left (C a^{3} + 3 \, B a^{2} b - 3 \, C a b^{2} - B b^{3}\right )} \log \left (\frac{\tan \left (d x + c\right )^{2}}{\tan \left (d x + c\right )^{2} + 1}\right ) \tan \left (d x + c\right )^{5} + 15 \,{\left (3 \, C a^{3} + 9 \, B a^{2} b - 6 \, C a b^{2} - 2 \, B b^{3} - 4 \,{\left (B a^{3} - 3 \, C a^{2} b - 3 \, B a b^{2} + C b^{3}\right )} d x\right )} \tan \left (d x + c\right )^{5} - 60 \,{\left (B a^{3} - 3 \, C a^{2} b - 3 \, B a b^{2} + C b^{3}\right )} \tan \left (d x + c\right )^{4} - 12 \, B a^{3} + 30 \,{\left (C a^{3} + 3 \, B a^{2} b - 3 \, C a b^{2} - B b^{3}\right )} \tan \left (d x + c\right )^{3} + 20 \,{\left (B a^{3} - 3 \, C a^{2} b - 3 \, B a b^{2}\right )} \tan \left (d x + c\right )^{2} - 15 \,{\left (C a^{3} + 3 \, B a^{2} b\right )} \tan \left (d x + c\right )}{60 \, d \tan \left (d x + c\right )^{5}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 3.01282, size = 905, normalized size = 3.88 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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